United States presidential election in Delaware, 1948
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All 3 Delaware votes to the Electoral College |
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The 1948 United States presidential election in Delaware took place on November 2, 1948, as part of the 1948 United States presidential election. Delaware voters chose three[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.
Delaware was won by Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 50.04% of the popular vote, against incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 48.76% of the popular vote.[3][4]
Results
| United States presidential election in Delaware, 1948 | ||||
|---|---|---|---|---|
| Party | Candidate | Votes | % | |
| Republican | Thomas Dewey | 69,588 | 50.04% | |
| Democratic | Harry S. Truman (inc.) | 67,813 | 48.76% | |
| Progressive | Henry A. Wallace | 1,050 | 0.75% | |
| Write-in | 622 | 0.45% | ||
| Total votes | 139,073 | 100% | ||
References
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| General articles |
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| Local results |
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| Other 1948 elections |
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